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-5x^2=23x+24
We move all terms to the left:
-5x^2-(23x+24)=0
We get rid of parentheses
-5x^2-23x-24=0
a = -5; b = -23; c = -24;
Δ = b2-4ac
Δ = -232-4·(-5)·(-24)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-7}{2*-5}=\frac{16}{-10} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+7}{2*-5}=\frac{30}{-10} =-3 $
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